Use the bisection method on f(x) = x³ − x − 3 with the starting interval [1, 2]. Find the midpoint c3 of step 3.
Numerical methods worksheet with answers
1.Easy
f(x) = x³ − x − 3[a, b] = [1, 2]n = 3
c3 =
2.Easy
Apply Newton–Raphson to f(x) = cos x − x with the starting value x₀ = 0. Find x1.
f(x) = cos x − xf′(x) = −sin x − 1x₀ = 0
x1 =
3.Medium
Approximate ∫01.5 √(1 + x³) dx with the trapezoid rule using n = 5 strips. Give T.
f(x) = √(1 + x³)[a, b] = [0, 1.5]n = 5
T =
4.Medium
Approximate ∫01 sin(x²) dx with the trapezoid rule using n = 6 strips. Give T.
f(x) = sin(x²)[a, b] = [0, 1]n = 6
T =
5.Hard
Use Heun's method (improved Euler) with h = 0.1 for y′ = cos t − y, y(0) = 1 to estimate y2 ≈ y(0.2).
y′ = cos t − yy(0) = 1h = 0.1
y2 =
6.Hard
Use Heun's method (improved Euler) with h = 0.5 for y′ = 1 + sin(ty), y(0) = 0.5 to estimate y3 ≈ y(1.5).
y′ = 1 + sin(ty)y(0) = 0.5h = 0.5
y3 =
Answer key
- 1. c3 = 1.625
- 2. x1 = 1
- 3. T = 1.989
- 4. T = 0.3128
- 5. y2 = 0.9986
- 6. y3 = 2.479
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