Op-amp circuits worksheet with answers

Free printable Op-amp circuits worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
−+Vout​10 VRs​ = 47 kΩRL​0.47 kΩ

A sensor behaves like a 10 V source with an internal resistance Rs = 47 kΩ. It feeds a load RL = 0.47 kΩ through an ideal voltage follower (unity-gain buffer). For comparison, find the load voltage VL if the load were connected directly to the sensor without the buffer.

Vs = 10 VRs = 47 kΩRL = 0.47 kΩ
VL = V
2.Easy
−+Vout​Rf​ = ?Vin​R1​ = 1 kΩ

An inverting amplifier with an ideal op-amp must have a voltage gain of −10. The input resistor is R1 = 1 kΩ. Find the feedback resistor Rf.

Av = −10R1 = 1 kΩ
Rf = kΩ
3.Medium
−+Vout​Rf​ = 47 kΩR1​ = 47 kΩVin​ = −1 V

The op-amp is ideal and runs from ±15 V supplies. Find the output voltage Vout.

Vin = −1 VR1 = 47 kΩRf = 47 kΩ
Vout = V
4.Medium
−+Vout​R2​ = 2 kΩV1​ = 0.3 VR1​ = 22 kΩV2​ = 2.7 VR3​ = 22 kΩR4​ = 2 kΩ

The difference amplifier uses an ideal op-amp with ±15 V supplies, with R3 = R1 and R4 = R2. Find the output voltage Vout.

V1 = 0.3 VV2 = 2.7 VR1 = R3 = 22 kΩR2 = R4 = 2 kΩ
Vout = V
5.Hard
−+Vout​R2​ = 100 kΩV1​ = −1.5 VR1​ = 47 kΩV2​ = 1 VR3​ = 1 kΩR4​ = 22 kΩ

The op-amp is ideal and runs from ±15 V supplies. The resistor ratios are not matched. Find the output voltage Vout.

V1 = −1.5 VV2 = 1 VR1 = 47 kΩR2 = 100 kΩR3 = 1 kΩR4 = 22 kΩ
Vout = V
6.Hard
−+Vout​Rf​ = 1 kΩV1​ = 1.7 VR1​ = 47 kΩV2​ = −1.5 VR2​ = 2 kΩ

The summing amplifier uses an ideal op-amp with ±15 V supplies. Find the output voltage Vout.

V1 = 1.7 VV2 = −1.5 VR1 = 47 kΩR2 = 2 kΩRf = 1 kΩ
Vout = V

Answer key

  1. 1. VL = 0.09901 V
  2. 2. Rf = 10 kΩ
  3. 3. Vout = −2 V
  4. 4. Vout = 0.2182 V
  5. 5. Vout = 6.183 V
  6. 6. Vout = 0.7138 V

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