Op-amp circuits worksheet with answers

Free printable Op-amp circuits worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
−+Vout​Rf​ = 22 kΩVin​ = 2 VR1​ = 2 kΩ

The circuit is an inverting amplifier. The op-amp is ideal and runs from ±15 V supplies; its output saturates at ±12 V. Find the output voltage Vout.

Vin = 2 VR1 = 2 kΩRf = 22 kΩVsat = ±12 V
Vout = V
2.Easy
−+Vout​Rf​ = 22 kΩVin​ = −2 VR1​ = 1 kΩ

The circuit is an inverting amplifier. The op-amp is ideal and runs from ±15 V supplies; its output saturates at ±13 V. Find the output voltage Vout.

Vin = −2 VR1 = 1 kΩRf = 22 kΩVsat = ±13 V
Vout = V
3.Medium
−+Vout​Rf​ = 22 kΩR1​ = 10 kΩVin​ = 3 VRa​ = 22 kΩRb​ = 47 kΩ

The op-amp is ideal and runs from ±15 V supplies. Find the output voltage Vout.

Vin = 3 VRa = 22 kΩRb = 47 kΩR1 = 10 kΩRf = 22 kΩ
Vout = V
4.Medium
−+Vout​R2​ = 100 kΩV1​ = −0.2 VR1​ = 47 kΩV2​ = 1.9 VR3​ = 47 kΩR4​ = 100 kΩ

The difference amplifier uses an ideal op-amp with ±15 V supplies, with R3 = R1 and R4 = R2. Find the output voltage Vout.

V1 = −0.2 VV2 = 1.9 VR1 = R3 = 47 kΩR2 = R4 = 100 kΩ
Vout = V
5.Hard
−+Vout​C = 2.2 µFVin​ = −2.6 VR = 100 kΩ

The integrator uses an ideal op-amp with ±15 V supplies; its output saturates at ±13 V. The capacitor is uncharged when a constant input Vin = −2.6 V is applied at t = 0. Find the output voltage Vout at t = 100 ms.

Vin = −2.6 VR = 100 kΩC = 2.2 µFVsat = ±13 Vt = 100 ms
Vout = V
6.Hard
−+Vout​Rf​ = 100 kΩV1​ = −0.4 VR1​ = 100 kΩV2​ = −1.3 VR2​ = 22 kΩ

The summing amplifier uses an ideal op-amp with ±15 V supplies. Find the output voltage Vout.

V1 = −0.4 VV2 = −1.3 VR1 = 100 kΩR2 = 22 kΩRf = 100 kΩ
Vout = V

Answer key

  1. 1. Vout = −12 V
  2. 2. Vout = 13 V
  3. 3. Vout = 6.539 V
  4. 4. Vout = 4.468 V
  5. 5. Vout = 1.182 V
  6. 6. Vout = 6.309 V

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