Rigid-body rotation worksheet with answers

Free printable Rigid-body rotation worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
Or = 0.1 mL = 0.4 m0.5 m4 kg8.5 kg

A pendulum is made of a uniform slender rod (4 kg, 0.4 m long) pivoted at its top end O, with a solid sphere of mass 8.5 kg and radius 0.1 m fixed to its lower end. The centre of the sphere is 0.5 m below O. Find the mass moment of inertia IO of the pendulum about O.

mrod = 4 kgL = 0.4 mmsphere = 8.5 kgr = 0.1 md = 0.5 m
IO = kg·m²
2.Easy
L = 2.3 mGOd = 0.7 mm = 4.5 kg

A uniform slender rod of mass 4.5 kg and length 2.3 m rotates about an axis O perpendicular to the rod, 0.7 m from its centre G. Find its mass moment of inertia IO about that axis.

m = 4.5 kgL = 2.3 md = 0.7 m
IO = kg·m²
3.Medium
0 → 2600 rpmI = 6 kg·m²

A motor brings a flywheel with a moment of inertia of 6 kg·m² from rest up to 2600 rpm in 48 s. Ignoring losses, find the average power Pavg it delivers, in kW.

I = 6 kg·m²n = 2600 rpmt = 48 s
Pavg = kW
4.Medium
n = 1900 rpmTb​ = 150 N·mI = 24 kg·m²

A flywheel with a moment of inertia of 24 kg·m² spins at 1900 rpm. A brake applies a constant friction torque of 150 N·m. How long t does it take to stop?

I = 24 kg·m²n = 1900 rpmTb = 150 N·m
t = s
5.Hard
320 m/s30 g0.93 mL = 1.7 m6.5 kgφ

A uniform slender rod of mass 6.5 kg and length 1.7 m hangs at rest from a frictionless pivot at its top end. A 30 g bullet moving horizontally at 320 m/s hits the rod 0.93 m below the pivot and stays embedded. Use g = 9.81 m/s². Find the largest angle φ from the vertical through which the rod swings.

M = 6.5 kgL = 1.7 mm = 30 gv = 320 m/sd = 0.93 mg = 9.81 m/s²
φ = °
6.Hard
7 m/sω

A solid sphere of mass 12.5 kg rolls without slipping at 7 m/s. What percentage p of its total kinetic energy is rotational?

m = 12.5 kgv = 7 m/sI = (2/5)·m·r²
p = %

Answer key

  1. 1. IO = 2.372 kg·m²
  2. 2. IO = 4.189 kg·m²
  3. 3. Pavg = 4.633 kW
  4. 4. t = 31.83 s
  5. 5. φ = 27.92 °
  6. 6. p = 28.57 %

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