Rigid-body rotation worksheet with answers

Free printable Rigid-body rotation worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

For teachers: free to print, copy and use in class. Every new worksheet has new values and its own answer key. A link to ExamProblems on your course page is appreciated.

Name: ____________________   Date: ____________

1.Easy
Or = 0.2 mL = 0.7 m0.9 m2 kg1.5 kg

A pendulum is made of a uniform slender rod (2 kg, 0.7 m long) pivoted at its top end O, with a thin solid disc of mass 1.5 kg and radius 0.2 m fixed to its lower end. The disc swings in its own plane and its centre is 0.9 m below O. Find the mass moment of inertia IO of the pendulum about O.

mrod = 2 kgL = 0.7 mmdisc = 1.5 kgr = 0.2 md = 0.9 m
IO = kg·m²
2.Easy
L = 0.9 mGOd = 0.25 mm = 1 kg

A uniform slender rod of mass 1 kg and length 0.9 m rotates about an axis O perpendicular to the rod, 0.25 m from its centre G. Find its mass moment of inertia IO about that axis.

m = 1 kgL = 0.9 md = 0.25 m
IO = kg·m²
3.Medium
n = 500 rpmTb​ = 65 N·mI = 25 kg·m²

A flywheel with a moment of inertia of 25 kg·m² spins at 500 rpm. A brake applies a constant friction torque of 65 N·m. How long t does it take to stop?

I = 25 kg·m²n = 500 rpmTb = 65 N·m
t = s
4.Medium
ω = ?L = 0.5 mm = 1.5 kg

A uniform slender rod of mass 1.5 kg and length 0.5 m is pinned at one end and released from rest in a horizontal position. Ignore friction and use g = 9.81 m/s². Find the angular velocity ω of the rod as it swings through the vertical position.

m = 1.5 kgL = 0.5 mg = 9.81 m/s²
ω = rad/s
5.Hard
0.6 m0.15 mn1​ = 25 rpm

A person stands on a frictionless turntable and holds a 2.5 kg dumbbell in each hand, 0.6 m from the axis. The person and turntable alone have a moment of inertia of 2 kg·m² about the axis. They turn at 25 rpm, then pull the dumbbells in to 0.15 m from the axis. Treat the dumbbells as point masses. Find the new speed n2 in rpm.

I0 = 2 kg·m²m = 2 × 2.5 kgr1 = 0.6 mr2 = 0.15 mn1 = 25 rpm
n2 = rpm
6.Hard
θ = 40°vs = 6 m

A hollow sphere starts from rest and rolls without slipping down a slope inclined at 40° to the horizontal. Use g = 9.81 m/s². Its radius is 0.25 m. Find its angular velocity ω after it has rolled 6 m along the slope.

θ = 40°s = 6 mI = (2/3)·m·r²g = 9.81 m/s²r = 0.25 m
ω = rad/s

Answer key

  1. 1. IO = 1.572 kg·m²
  2. 2. IO = 0.13 kg·m²
  3. 3. t = 20.14 s
  4. 4. ω = 7.672 rad/s
  5. 5. n2 = 44.97 rpm
  6. 6. ω = 26.95 rad/s

Full step-by-step solutions: practise this topic on examproblems.com.