Rigid-body rotation worksheet with answers

Free printable Rigid-body rotation worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

For teachers: free to print, copy and use in class. Every new worksheet has new values and its own answer key. A link to ExamProblems on your course page is appreciated.

Name: ____________________   Date: ____________

1.Easy
k = 0.15 m600 → 2300 rpm20 kg

A flywheel of mass 20 kg with a radius of gyration of 0.15 m is accelerated uniformly from 600 rpm to 2300 rpm. The driving torque is a constant 8 N·m and friction can be ignored. How long t does this take?

m = 20 kgk = 0.15 mn1 = 600 rpmn2 = 2300 rpmT = 8 N·m
t = s
2.Easy
L = 2 mGOd = 0.4 mm = 2.5 kg

A uniform slender rod of mass 2.5 kg and length 2 m rotates about an axis O perpendicular to the rod, 0.4 m from its centre G. Find its mass moment of inertia IO about that axis.

m = 2.5 kgL = 2 md = 0.4 m
IO = kg·m²
3.Medium
0 → 2000 rpmI = 12 kg·m²

A motor brings a flywheel with a moment of inertia of 12 kg·m² from rest up to 2000 rpm in 41 s. Ignoring losses, find the average power Pavg it delivers, in kW.

I = 12 kg·m²n = 2000 rpmt = 41 s
Pavg = kW
4.Medium
3 kgaαM = 11.5 kgR = 0.15 m

A 3 kg block hangs from a light cord wrapped around a pulley, a uniform solid disc of mass 11.5 kg and radius 0.15 m that turns on a frictionless horizontal axle. The block is released from rest. Use g = 9.81 m/s². Find the angular acceleration α of the pulley.

m = 3 kgM = 11.5 kgR = 0.15 mg = 9.81 m/s²
α = rad/s²
5.Hard
0.8 m0.2 mn1​ = 45 rpm

A person stands on a frictionless turntable and holds a 4 kg dumbbell in each hand, 0.8 m from the axis. The person and turntable alone have a moment of inertia of 4 kg·m² about the axis. They turn at 45 rpm, then pull the dumbbells in to 0.2 m from the axis. Treat the dumbbells as point masses. Find the new speed n2 in rpm.

I0 = 4 kg·m²m = 2 × 4 kgr1 = 0.8 mr2 = 0.2 mn1 = 45 rpm
n2 = rpm
6.Hard
θ = 15°vs = 10 m

A hollow sphere starts from rest and rolls without slipping down a slope inclined at 15° to the horizontal. Use g = 9.81 m/s². Find its speed v after it has rolled 10 m along the slope.

θ = 15°s = 10 mI = (2/3)·m·r²g = 9.81 m/s²
v = m/s

Answer key

  1. 1. t = 10.01 s
  2. 2. IO = 1.233 kg·m²
  3. 3. Pavg = 6.419 kW
  4. 4. α = 22.42 rad/s²
  5. 5. n2 = 95 rpm
  6. 6. v = 5.52 m/s

Full step-by-step solutions: practise this topic on examproblems.com.