Rigid-body rotation worksheet with answers

Free printable Rigid-body rotation worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
Or = 0.1 mL = 0.5 m0.6 m4 kg6 kg

A pendulum is made of a uniform slender rod (4 kg, 0.5 m long) pivoted at its top end O, with a thin solid disc of mass 6 kg and radius 0.1 m fixed to its lower end. The disc swings in its own plane and its centre is 0.6 m below O. Find the mass moment of inertia IO of the pendulum about O.

mrod = 4 kgL = 0.5 mmdisc = 6 kgr = 0.1 md = 0.6 m
IO = kg·m²
2.Easy
Or = 0.15 mL = 1 m1.15 m1 kg8 kg

A pendulum is made of a uniform slender rod (1 kg, 1 m long) pivoted at its top end O, with a solid sphere of mass 8 kg and radius 0.15 m fixed to its lower end. The centre of the sphere is 1.15 m below O. Find the mass moment of inertia IO of the pendulum about O.

mrod = 1 kgL = 1 mmsphere = 8 kgr = 0.15 md = 1.15 m
IO = kg·m²
3.Medium
n = 800 rpmTb​ = 60 N·mI = 34 kg·m²

A flywheel with a moment of inertia of 34 kg·m² spins at 800 rpm. A brake applies a constant friction torque of 60 N·m. How long t does it take to stop?

I = 34 kg·m²n = 800 rpmTb = 60 N·m
t = s
4.Medium
n = 2500 rpmTb​ = 125 N·mI = 6 kg·m²

A flywheel with a moment of inertia of 6 kg·m² spins at 2500 rpm. A brake applies a constant friction torque of 125 N·m. How many revolutions N does the flywheel make before it stops?

I = 6 kg·m²n = 2500 rpmTb = 125 N·m
N = rev
5.Hard
580 m/s15 g0.72 mL = 0.8 m10 kgφ

A uniform slender rod of mass 10 kg and length 0.8 m hangs at rest from a frictionless pivot at its top end. A 15 g bullet moving horizontally at 580 m/s hits the rod 0.72 m below the pivot and stays embedded. Use g = 9.81 m/s². Find the largest angle φ from the vertical through which the rod swings.

M = 10 kgL = 0.8 mm = 15 gv = 580 m/sd = 0.72 mg = 9.81 m/s²
φ = °
6.Hard
θ = 20°vs = 7 m

A solid cylinder starts from rest and rolls without slipping down a slope inclined at 20° to the horizontal. Use g = 9.81 m/s². Its radius is 0.35 m. Find its angular velocity ω after it has rolled 7 m along the slope.

θ = 20°s = 7 mI = ½·m·r²g = 9.81 m/s²r = 0.35 m
ω = rad/s

Answer key

  1. 1. IO = 2.523 kg·m²
  2. 2. IO = 10.99 kg·m²
  3. 3. t = 47.47 s
  4. 4. N = 261.8 rev
  5. 5. φ = 39.9 °
  6. 6. ω = 15.99 rad/s

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