For the reaction 2Mg + O2 → 2MgO, what mass m of MgO forms from 5 g of Mg? Assume the other reactants are in excess.
Stoichiometry worksheet with answers
1.Easy
M(Mg) = 24.31 g/molM(MgO) = 40.3 g/mol
m = g
2.Easy
For the reaction 2Na + Cl2 → 2NaCl, what mass m of NaCl forms from 32 g of Na? Assume the other reactants are in excess.
M(Na) = 22.99 g/molM(NaCl) = 58.44 g/mol
m = g
3.Medium
20 g of CH4 and 10 g of O2 react according to CH4 + 2O2 → CO2 + 2H2O. What mass m of CO2 can form?
M(CH4) = 16.04M(O2) = 32M(CO2) = 44.01 g/mol
m = g
4.Medium
20 g of N2 and 48 g of H2 react according to N2 + 3H2 → 2NH3. What mass m of NH3 can form?
M(N2) = 28.02M(H2) = 2.016M(NH3) = 17.03 g/mol
m = g
5.Hard
In the reaction 2Mg + O2 → 2MgO, 12 g of Mg reacts completely (the other reactants are in excess) and 16.31 g of MgO is collected. Find the percent yield Y.
M(Mg) = 24.31 g/molM(MgO) = 40.3 g/molactual: 16.31 g
Y = %
6.Hard
In the reaction 2Na + Cl2 → 2NaCl, 10 g of Na reacts completely (the other reactants are in excess) and 15.76 g of NaCl is collected. Find the percent yield Y.
M(Na) = 22.99 g/molM(NaCl) = 58.44 g/molactual: 15.76 g
Y = %
Answer key
- 1. m = 8.289 g
- 2. m = 81.34 g
- 3. m = 6.877 g
- 4. m = 24.31 g
- 5. Y = 81.99 %
- 6. Y = 62 %
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