For the reaction C6H12O6 → 2C2H5OH + 2CO2, what mass m of C2H5OH forms from 20 g of C6H12O6? Assume the other reactants are in excess.
Stoichiometry worksheet with answers
1.Easy
M(C6H12O6) = 180.16 g/molM(C2H5OH) = 46.07 g/mol
m = g
2.Easy
For the reaction N2 + 3H2 → 2NH3, what mass m of NH3 forms from 20 g of N2? Assume the other reactants are in excess.
M(N2) = 28.02 g/molM(NH3) = 17.03 g/mol
m = g
3.Medium
16 g of Mg and 16 g of O2 react according to 2Mg + O2 → 2MgO. What mass m of MgO can form?
M(Mg) = 24.31M(O2) = 32M(MgO) = 40.3 g/mol
m = g
4.Medium
20 g of H2 and 16 g of O2 react according to 2H2 + O2 → 2H2O. What mass m of H2O can form?
M(H2) = 2.016M(O2) = 32M(H2O) = 18.02 g/mol
m = g
5.Hard
In the reaction C6H12O6 → 2C2H5OH + 2CO2, 6 g of C6H12O6 reacts completely (the other reactants are in excess) and 2.3 g of C2H5OH is collected. Find the percent yield Y.
M(C6H12O6) = 180.16 g/molM(C2H5OH) = 46.07 g/molactual: 2.3 g
Y = %
6.Hard
In the reaction 2H2 + O2 → 2H2O, 30 g of H2 reacts completely (the other reactants are in excess) and 209.2 g of H2O is collected. Find the percent yield Y.
M(H2) = 2.016 g/molM(H2O) = 18.02 g/molactual: 209.2 g
Y = %
Answer key
- 1. m = 10.23 g
- 2. m = 24.31 g
- 3. m = 26.52 g
- 4. m = 18.02 g
- 5. Y = 74.95 %
- 6. Y = 78 %
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