For the reaction C6H12O6 → 2C2H5OH + 2CO2, what mass m of CO2 forms from 40 g of C6H12O6? Assume the other reactants are in excess.
Stoichiometry worksheet with answers
1.Easy
M(C6H12O6) = 180.16 g/molM(CO2) = 44.01 g/mol
m = g
2.Easy
For the reaction C3H8 + 5O2 → 3CO2 + 4H2O, what mass m of H2O forms from 8 g of C3H8? Assume the other reactants are in excess.
M(C3H8) = 44.1 g/molM(H2O) = 18.02 g/mol
m = g
3.Medium
16 g of Na and 20 g of Cl2 react according to 2Na + Cl2 → 2NaCl. What mass m of NaCl can form?
M(Na) = 22.99M(Cl2) = 70.9M(NaCl) = 58.44 g/mol
m = g
4.Medium
16 g of Mg and 8 g of O2 react according to 2Mg + O2 → 2MgO. What mass m of MgO can form?
M(Mg) = 24.31M(O2) = 32M(MgO) = 40.3 g/mol
m = g
5.Hard
In the reaction C3H8 + 5O2 → 3CO2 + 4H2O, 6 g of C3H8 reacts completely (the other reactants are in excess) and 8.04 g of H2O is collected. Find the percent yield Y.
M(C3H8) = 44.1 g/molM(H2O) = 18.02 g/molactual: 8.04 g
Y = %
6.Hard
In the reaction C3H8 + 5O2 → 3CO2 + 4H2O, 12 g of C3H8 reacts completely (the other reactants are in excess) and 33.77 g of CO2 is collected. Find the percent yield Y.
M(C3H8) = 44.1 g/molM(CO2) = 44.01 g/molactual: 33.77 g
Y = %
Answer key
- 1. m = 19.54 g
- 2. m = 13.08 g
- 3. m = 32.97 g
- 4. m = 20.15 g
- 5. Y = 81.98 %
- 6. Y = 94 %
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