For the reaction 2Al + 3Cl2 → 2AlCl3, what mass m of AlCl3 forms from 5 g of Al? Assume the other reactants are in excess.
Stoichiometry worksheet with answers
1.Easy
M(Al) = 26.98 g/molM(AlCl3) = 133.33 g/mol
m = g
2.Easy
For the reaction CH4 + 2O2 → CO2 + 2H2O, what mass m of H2O forms from 12 g of CH4? Assume the other reactants are in excess.
M(CH4) = 16.04 g/molM(H2O) = 18.02 g/mol
m = g
3.Medium
6 g of Al and 32 g of Cl2 react according to 2Al + 3Cl2 → 2AlCl3. What mass m of AlCl3 can form?
M(Al) = 26.98M(Cl2) = 70.9M(AlCl3) = 133.33 g/mol
m = g
4.Medium
8 g of Fe2O3 and 80 g of CO react according to Fe2O3 + 3CO → 2Fe + 3CO2. What mass m of Fe can form?
M(Fe2O3) = 159.69M(CO) = 28.01M(Fe) = 55.85 g/mol
m = g
5.Hard
In the reaction N2 + 3H2 → 2NH3, 20 g of N2 reacts completely (the other reactants are in excess) and 22.12 g of NH3 is collected. Find the percent yield Y.
M(N2) = 28.02 g/molM(NH3) = 17.03 g/molactual: 22.12 g
Y = %
6.Hard
In the reaction C3H8 + 5O2 → 3CO2 + 4H2O, 30 g of C3H8 reacts completely (the other reactants are in excess) and 62.87 g of CO2 is collected. Find the percent yield Y.
M(C3H8) = 44.1 g/molM(CO2) = 44.01 g/molactual: 62.87 g
Y = %
Answer key
- 1. m = 24.71 g
- 2. m = 26.96 g
- 3. m = 29.65 g
- 4. m = 5.596 g
- 5. Y = 90.99 %
- 6. Y = 70 %
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