Stoichiometry worksheet with answers

Free printable Stoichiometry worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

New worksheetPractise online with hints

For teachers: free to print, copy and use in class. Every new worksheet has new values and its own answer key. A link to ExamProblems on your course page is appreciated.

Name: ____________________   Date: ____________

1.Easy
m(Fe2​O3​)n(Fe2​O3​)n(Fe)m(Fe)÷ M(Fe2​O3​)× 2/1× M(Fe)

For the reaction Fe2O3 + 3CO → 2Fe + 3CO2, what mass m of Fe forms from 16 g of Fe2O3? Assume the other reactants are in excess.

M(Fe2O3) = 159.69 g/molM(Fe) = 55.85 g/mol
m = g
2.Easy
m(C6​H12​O6​)n(C6​H12​O6​)n(C2​H5​OH)m(C2​H5​OH)÷ M(C6​H12​O6​)× 2/1× M(C2​H5​OH)

For the reaction C6H12O6 → 2C2H5OH + 2CO2, what mass m of C2H5OH forms from 64 g of C6H12O6? Assume the other reactants are in excess.

M(C6H12O6) = 180.16 g/molM(C2H5OH) = 46.07 g/mol
m = g
3.Medium
m(X)n(X)n(CO2​)m(CO2​)÷ M(X)× 1/ν× M(CO2​)

30 g of CH4 and 8 g of O2 react according to CH4 + 2O2 → CO2 + 2H2O. What mass m of CO2 can form?

M(CH4) = 16.04M(O2) = 32M(CO2) = 44.01 g/mol
m = g
4.Medium
m(X)n(X)n(NH3​)m(NH3​)÷ M(X)× 2/ν× M(NH3​)

24 g of N2 and 24 g of H2 react according to N2 + 3H2 → 2NH3. What mass m of NH3 can form?

M(N2) = 28.02M(H2) = 2.016M(NH3) = 17.03 g/mol
m = g
5.Hard
m(Na)n(Na)n(NaCl)m(NaCl)÷ M(Na)× 2/2× M(NaCl)

In the reaction 2Na + Cl2 → 2NaCl, 12 g of Na reacts completely (the other reactants are in excess) and 16.78 g of NaCl is collected. Find the percent yield Y.

M(Na) = 22.99 g/molM(NaCl) = 58.44 g/molactual: 16.78 g
Y = %
6.Hard
m(Mg)n(Mg)n(MgO)m(MgO)÷ M(Mg)× 2/2× M(MgO)

In the reaction 2Mg + O2 → 2MgO, 24 g of Mg reacts completely (the other reactants are in excess) and 35.01 g of MgO is collected. Find the percent yield Y.

M(Mg) = 24.31 g/molM(MgO) = 40.3 g/molactual: 35.01 g
Y = %

Answer key

  1. 1. m = 11.19 g
  2. 2. m = 32.73 g
  3. 3. m = 5.501 g
  4. 4. m = 29.17 g
  5. 5. Y = 55.01 %
  6. 6. Y = 88 %

Full step-by-step solutions: practise this topic on examproblems.com.