For the reaction C3H8 + 5O2 → 3CO2 + 4H2O, what mass m of H2O forms from 20 g of C3H8? Assume the other reactants are in excess.
Stoichiometry worksheet with answers
1.Easy
M(C3H8) = 44.1 g/molM(H2O) = 18.02 g/mol
m = g
2.Easy
For the reaction 2H2 + O2 → 2H2O, what mass m of H2O forms from 10 g of H2? Assume the other reactants are in excess.
M(H2) = 2.016 g/molM(H2O) = 18.02 g/mol
m = g
3.Medium
6 g of N2 and 10 g of H2 react according to N2 + 3H2 → 2NH3. What mass m of NH3 can form?
M(N2) = 28.02M(H2) = 2.016M(NH3) = 17.03 g/mol
m = g
4.Medium
6 g of H2 and 40 g of O2 react according to 2H2 + O2 → 2H2O. What mass m of H2O can form?
M(H2) = 2.016M(O2) = 32M(H2O) = 18.02 g/mol
m = g
5.Hard
In the reaction 2Al + 3Cl2 → 2AlCl3, 24 g of Al reacts completely (the other reactants are in excess) and 88.95 g of AlCl3 is collected. Find the percent yield Y.
M(Al) = 26.98 g/molM(AlCl3) = 133.33 g/molactual: 88.95 g
Y = %
6.Hard
In the reaction C6H12O6 → 2C2H5OH + 2CO2, 24 g of C6H12O6 reacts completely (the other reactants are in excess) and 9.57 g of C2H5OH is collected. Find the percent yield Y.
M(C6H12O6) = 180.16 g/molM(C2H5OH) = 46.07 g/molactual: 9.57 g
Y = %
Answer key
- 1. m = 32.69 g
- 2. m = 89.38 g
- 3. m = 7.293 g
- 4. m = 45.05 g
- 5. Y = 75 %
- 6. Y = 77.97 %
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