For the reaction N2 + 3H2 → 2NH3, what mass m of NH3 forms from 16 g of N2? Assume the other reactants are in excess.
Stoichiometry worksheet with answers
1.Easy
M(N2) = 28.02 g/molM(NH3) = 17.03 g/mol
m = g
2.Easy
For the reaction 2Al + 3Cl2 → 2AlCl3, what mass m of AlCl3 forms from 32 g of Al? Assume the other reactants are in excess.
M(Al) = 26.98 g/molM(AlCl3) = 133.33 g/mol
m = g
3.Medium
30 g of C3H8 and 40 g of O2 react according to C3H8 + 5O2 → 3CO2 + 4H2O. What mass m of CO2 can form?
M(C3H8) = 44.1M(O2) = 32M(CO2) = 44.01 g/mol
m = g
4.Medium
10 g of CH4 and 8 g of O2 react according to CH4 + 2O2 → CO2 + 2H2O. What mass m of CO2 can form?
M(CH4) = 16.04M(O2) = 32M(CO2) = 44.01 g/mol
m = g
5.Hard
In the reaction C6H12O6 → 2C2H5OH + 2CO2, 8 g of C6H12O6 reacts completely (the other reactants are in excess) and 3.19 g of C2H5OH is collected. Find the percent yield Y.
M(C6H12O6) = 180.16 g/molM(C2H5OH) = 46.07 g/molactual: 3.19 g
Y = %
6.Hard
In the reaction C6H12O6 → 2C2H5OH + 2CO2, 30 g of C6H12O6 reacts completely (the other reactants are in excess) and 9.51 g of C2H5OH is collected. Find the percent yield Y.
M(C6H12O6) = 180.16 g/molM(C2H5OH) = 46.07 g/molactual: 9.51 g
Y = %
Answer key
- 1. m = 19.45 g
- 2. m = 158.1 g
- 3. m = 33.01 g
- 4. m = 5.501 g
- 5. Y = 77.97 %
- 6. Y = 61.98 %
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