For the reaction Fe2O3 + 3CO → 2Fe + 3CO2, what mass m of Fe forms from 50 g of Fe2O3? Assume the other reactants are in excess.
Stoichiometry worksheet with answers
1.Easy
M(Fe2O3) = 159.69 g/molM(Fe) = 55.85 g/mol
m = g
2.Easy
For the reaction 2H2 + O2 → 2H2O, what mass m of H2O forms from 100 g of H2? Assume the other reactants are in excess.
M(H2) = 2.016 g/molM(H2O) = 18.02 g/mol
m = g
3.Medium
20 g of Fe2O3 and 64 g of CO react according to Fe2O3 + 3CO → 2Fe + 3CO2. What mass m of Fe can form?
M(Fe2O3) = 159.69M(CO) = 28.01M(Fe) = 55.85 g/mol
m = g
4.Medium
24 g of Al and 32 g of Cl2 react according to 2Al + 3Cl2 → 2AlCl3. What mass m of AlCl3 can form?
M(Al) = 26.98M(Cl2) = 70.9M(AlCl3) = 133.33 g/mol
m = g
5.Hard
In the reaction 2Na + Cl2 → 2NaCl, 16 g of Na reacts completely (the other reactants are in excess) and 25.22 g of NaCl is collected. Find the percent yield Y.
M(Na) = 22.99 g/molM(NaCl) = 58.44 g/molactual: 25.22 g
Y = %
6.Hard
In the reaction 2Na + Cl2 → 2NaCl, 4 g of Na reacts completely (the other reactants are in excess) and 8.64 g of NaCl is collected. Find the percent yield Y.
M(Na) = 22.99 g/molM(NaCl) = 58.44 g/molactual: 8.64 g
Y = %
Answer key
- 1. m = 34.97 g
- 2. m = 893.8 g
- 3. m = 13.99 g
- 4. m = 40.12 g
- 5. Y = 62.01 %
- 6. Y = 84.97 %
Full step-by-step solutions: practise this topic on examproblems.com.