Stoichiometry worksheet with answers

Free printable Stoichiometry worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

For teachers: free to print, copy and use in class. Every new worksheet has new values and its own answer key. A link to ExamProblems on your course page is appreciated.

Name: ____________________   Date: ____________

1.Easy
m(C6​H12​O6​)n(C6​H12​O6​)n(CO2​)m(CO2​)÷ M(C6​H12​O6​)× 2/1× M(CO2​)

For the reaction C6H12O6 → 2C2H5OH + 2CO2, what mass m of CO2 forms from 10 g of C6H12O6? Assume the other reactants are in excess.

M(C6H12O6) = 180.16 g/molM(CO2) = 44.01 g/mol
m = g
2.Easy
m(C6​H12​O6​)n(C6​H12​O6​)n(CO2​)m(CO2​)÷ M(C6​H12​O6​)× 2/1× M(CO2​)

For the reaction C6H12O6 → 2C2H5OH + 2CO2, what mass m of CO2 forms from 20 g of C6H12O6? Assume the other reactants are in excess.

M(C6H12O6) = 180.16 g/molM(CO2) = 44.01 g/mol
m = g
3.Medium
m(X)n(X)n(Fe)m(Fe)÷ M(X)× 2/ν× M(Fe)

30 g of Fe2O3 and 16 g of CO react according to Fe2O3 + 3CO → 2Fe + 3CO2. What mass m of Fe can form?

M(Fe2O3) = 159.69M(CO) = 28.01M(Fe) = 55.85 g/mol
m = g
4.Medium
m(X)n(X)n(CO2​)m(CO2​)÷ M(X)× 3/ν× M(CO2​)

20 g of C3H8 and 10 g of O2 react according to C3H8 + 5O2 → 3CO2 + 4H2O. What mass m of CO2 can form?

M(C3H8) = 44.1M(O2) = 32M(CO2) = 44.01 g/mol
m = g
5.Hard
m(H2​)n(H2​)n(H2​O)m(H2​O)÷ M(H2​)× 2/2× M(H2​O)

In the reaction 2H2 + O2 → 2H2O, 16 g of H2 reacts completely (the other reactants are in excess) and 117.3 g of H2O is collected. Find the percent yield Y.

M(H2) = 2.016 g/molM(H2O) = 18.02 g/molactual: 117.3 g
Y = %
6.Hard
m(C6​H12​O6​)n(C6​H12​O6​)n(C2​H5​OH)m(C2​H5​OH)÷ M(C6​H12​O6​)× 2/1× M(C2​H5​OH)

In the reaction C6H12O6 → 2C2H5OH + 2CO2, 16 g of C6H12O6 reacts completely (the other reactants are in excess) and 4.5 g of C2H5OH is collected. Find the percent yield Y.

M(C6H12O6) = 180.16 g/molM(C2H5OH) = 46.07 g/molactual: 4.5 g
Y = %

Answer key

  1. 1. m = 4.886 g
  2. 2. m = 9.771 g
  3. 3. m = 20.98 g
  4. 4. m = 8.252 g
  5. 5. Y = 82 %
  6. 6. Y = 54.99 %

Full step-by-step solutions: practise this topic on examproblems.com.