For the reaction C6H12O6 → 2C2H5OH + 2CO2, what mass m of CO2 forms from 10 g of C6H12O6? Assume the other reactants are in excess.
Stoichiometry worksheet with answers
1.Easy
M(C6H12O6) = 180.16 g/molM(CO2) = 44.01 g/mol
m = g
2.Easy
For the reaction C6H12O6 → 2C2H5OH + 2CO2, what mass m of CO2 forms from 20 g of C6H12O6? Assume the other reactants are in excess.
M(C6H12O6) = 180.16 g/molM(CO2) = 44.01 g/mol
m = g
3.Medium
30 g of Fe2O3 and 16 g of CO react according to Fe2O3 + 3CO → 2Fe + 3CO2. What mass m of Fe can form?
M(Fe2O3) = 159.69M(CO) = 28.01M(Fe) = 55.85 g/mol
m = g
4.Medium
20 g of C3H8 and 10 g of O2 react according to C3H8 + 5O2 → 3CO2 + 4H2O. What mass m of CO2 can form?
M(C3H8) = 44.1M(O2) = 32M(CO2) = 44.01 g/mol
m = g
5.Hard
In the reaction 2H2 + O2 → 2H2O, 16 g of H2 reacts completely (the other reactants are in excess) and 117.3 g of H2O is collected. Find the percent yield Y.
M(H2) = 2.016 g/molM(H2O) = 18.02 g/molactual: 117.3 g
Y = %
6.Hard
In the reaction C6H12O6 → 2C2H5OH + 2CO2, 16 g of C6H12O6 reacts completely (the other reactants are in excess) and 4.5 g of C2H5OH is collected. Find the percent yield Y.
M(C6H12O6) = 180.16 g/molM(C2H5OH) = 46.07 g/molactual: 4.5 g
Y = %
Answer key
- 1. m = 4.886 g
- 2. m = 9.771 g
- 3. m = 20.98 g
- 4. m = 8.252 g
- 5. Y = 82 %
- 6. Y = 54.99 %
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