Superposition worksheet with answers

Free printable Superposition worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy

Use superposition to find the contribution V_R3′ of V₁ alone to the voltage V_R3 across R₃ with the polarity shown.

V₁ = 18 VV₂ = 6 VR₁ = 6 ΩR₂ = 8 ΩR₃ = 4 Ω

V_R3′ = V

2.Easy

Use superposition to find the contribution V_R3″ of V₂ alone to the voltage V_R3 across R₃ with the polarity shown.

V₁ = 20 VV₂ = 10 VR₁ = 2 ΩR₂ = 6 ΩR₃ = 8 Ω

V_R3″ = V

3.Medium

Use superposition to find the voltage V_R2 across R₂ with the polarity shown.

V₁ = 15 VI_s = 5 AR₁ = 6 ΩR₂ = 4 ΩR₃ = 12 ΩR₄ = 15 Ω

V_R2 = V

4.Medium

Use superposition to find the power P_R4 absorbed by R₄.

V₁ = 10 VI_s = 5 AR₁ = 3 ΩR₂ = 3 ΩR₃ = 10 ΩR₄ = 5 Ω

P_R4 = W

5.Hard

Find the value of the voltage source V₂ (polarity as shown) that makes the current I_R3 through R₃ equal to zero.

V₁ = 30 VI_s = 3 AR₁ = 12 ΩR₂ = 3 ΩR₃ = 5 ΩR₄ = 25 Ω

V₂ = V

6.Hard

A linear resistive circuit contains three independent sources: V₁, V₂ and I_s. The current I through a load is measured three times. With all sources at their normal values, I = 28 mA. With V₁ doubled and the other two unchanged, I = 35.5 mA. With the direction of I_s reversed and the other two unchanged, I = 8 mA. Find the load current I when V₂ is switched off and V₁ and I_s have their normal values.

normal: I = 28 mA2·V₁: I = 35.5 mA−I_s: I = 8 mA

I = mA

Answer key

1. V_R3′ = 5.538 V
2. V_R3″ = 2.105 V
3. V_R2 = 11.63 V
4. P_R4 = 50.62 W
5. V₂ = 5 V
6. I = 17.5 mA

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