Superposition worksheet with answers

Free printable Superposition worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy

Use superposition to find the voltage V_R3 across R₃ with the polarity shown.

V₁ = 8 VV₂ = 24 VR₁ = 5 ΩR₂ = 5 ΩR₃ = 5 Ω

V_R3 = V

2.Easy

Use superposition to find the node voltage V_A (measured from ground).

V₁ = 15 VI_s = 3 AR₁ = 5 ΩR₂ = 2 Ω

V_A = V

3.Medium

Use superposition to find the current I_R1 through R₁ in the direction of the arrow.

V₁ = 10 VI_s = 1.5 AR₁ = 20 ΩR₂ = 5 ΩR₃ = 5 ΩR₄ = 15 Ω

I_R1 = A

4.Medium

A linear resistive circuit contains one voltage source V_s and one current source I_s. The current I through a load resistor is measured twice: with V_s = 20 V and I_s = 1 mA, I = 7.25 mA; with V_s = 20 V and I_s = 5 mA, I = 4.25 mA. Find the load current I when V_s = 8 V and I_s = 2 mA.

20 V, 1 mA → 7.25 mA20 V, 5 mA → 4.25 mAV_s = 8 V, I_s = 2 mA

I = mA

5.Hard

A linear resistive circuit contains three independent sources: V₁, V₂ and I_s. The current I through a load is measured three times. With all sources at their normal values, I = −10.5 mA. With V₁ doubled and the other two unchanged, I = −19 mA. With the direction of I_s reversed and the other two unchanged, I = 3.5 mA. Find the load current I when V₂ is switched off and V₁ and I_s have their normal values.

normal: I = −10.5 mA2·V₁: I = −19 mA−I_s: I = 3.5 mA

I = mA

6.Hard

Use superposition to find the power P_R1 absorbed by R₁.

V₁ = 36 VI_s = 5 AV₂ = 36 VR₁ = 10 ΩR₂ = 20 ΩR₃ = 4 ΩR₄ = 20 Ω

P_R1 = W

Answer key

1. V_R3 = 10.67 V
2. V_A = 8.571 V
3. I_R1 = 0.6042 A
4. I = 1.7 mA
5. I = −15.5 mA
6. P_R1 = 30.04 W

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