Superposition worksheet with answers

Free printable Superposition worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy

Use superposition to find the contribution V_R3″ of V₂ alone to the voltage V_R3 across R₃ with the polarity shown.

V₁ = 18 VV₂ = 8 VR₁ = 5 ΩR₂ = 6 ΩR₃ = 5 Ω

V_R3″ = V

2.Easy

Use superposition to find the voltage V_R3 across R₃ with the polarity shown.

V₁ = 12 VV₂ = 15 VR₁ = 3 ΩR₂ = 8 ΩR₃ = 2 Ω

V_R3 = V

3.Medium

A linear resistive circuit contains one voltage source V_s and one current source I_s. The current I through a load resistor is measured twice: with V_s = 12 V and I_s = 2 mA, I = 5.2 mA; with V_s = 20 V and I_s = 2 mA, I = 8.4 mA. Find the load current I when V_s = 10 V and I_s = 8 mA.

12 V, 2 mA → 5.2 mA20 V, 2 mA → 8.4 mAV_s = 10 V, I_s = 8 mA

I = mA

4.Medium

Find the value of the current source I_s (direction as shown) that makes the current I_R3 through R₃ equal to zero.

V₁ = 6 VR₁ = 2 ΩR₂ = 4 ΩR₃ = 12 ΩR₄ = 3 Ω

I_s = A

5.Hard

Use superposition to find the voltage V_R2 across R₂ with the polarity shown.

V₁ = 36 VI_s = 2.5 AV₂ = 24 VR₁ = 25 ΩR₂ = 20 ΩR₃ = 5 ΩR₄ = 8 Ω

V_R2 = V

6.Hard

Use superposition to find the current I_R3 through R₃ in the direction of the arrow.

V₁ = 30 VI_s = 1.5 AV₂ = 10 VR₁ = 8 ΩR₂ = 12 ΩR₃ = 8 ΩR₄ = 6 Ω

I_R3 = A

Answer key

1. V_R3″ = 2.353 V
2. V_R3 = 6.13 V
3. I = 5.6 mA
4. I_s = 1.333 A
5. V_R2 = 1.244 V
6. I_R3 = 1.557 A

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