Superposition worksheet with answers

Free printable Superposition worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
R1​ = 2 ΩR2​ = 8 Ω+−V1​24 VR3​2 ΩIR3​A+−V2​24 V

Use superposition to find the current IR3 through R3 in the direction of the arrow.

V1 = 24 VV2 = 24 VR1 = 2 ΩR2 = 8 ΩR3 = 2 Ω
IR3 = A
2.Easy
linear circuitV1​ = 24 VV2​ = 6 VIRL​

A linear resistive circuit contains two independent voltage sources, V1 = 24 V and V2 = 6 V. With both sources on, the current through the load resistor is I = 17 mA. With V2 switched off (replaced by a short circuit) and V1 unchanged, the load current is 13 mA. Find the load current I when V1 is raised to 48 V and V2 stays at 6 V.

I = 17 mA (both sources)I = 13 mA (only V1)
I = mA
3.Medium
linear circuitVs​Is​IRL​

A linear resistive circuit contains one voltage source Vs and one current source Is. The current I through a load resistor is measured twice: with Vs = 12 V and Is = 10 mA, I = 5.8 mA; with Vs = 15 V and Is = 10 mA, I = 7 mA. Find the load current I when Vs = 20 V and Is = 1 mA.

12 V, 10 mA → 5.8 mA15 V, 10 mA → 7 mAVs = 20 V, Is = 1 mA
I = mA
4.Medium
R1​ = 15 ΩIR1​R3​ = 3 Ω+−V1​30 VR2​6 ΩAR4​5 ΩBIs​2 A

Use superposition to find the current IR1 through R1 in the direction of the arrow.

V1 = 30 VIs = 2 AR1 = 15 ΩR2 = 6 ΩR3 = 3 ΩR4 = 5 Ω
IR1 = A
5.Hard
R1​ = 6 ΩR2​ = 2 ΩR4​ = 15 Ω+−V1​15 VR3​15 ΩIR3​AIs​5 AB+−V2​?

Find the value of the voltage source V2 (polarity as shown) that makes the current IR3 through R3 equal to zero.

V1 = 15 VIs = 5 AR1 = 6 ΩR2 = 2 ΩR3 = 15 ΩR4 = 15 Ω
V2 = V
6.Hard
R1​ = 12 ΩR2​ = 2 ΩR4​ = 10 Ω+−V1​6 VR3​25 Ω+−VR3​AIs​2 AB+−V2​18 V

Use superposition to find the voltage VR3 across R3 with the polarity shown.

V1 = 6 VIs = 2 AV2 = 18 VR1 = 12 ΩR2 = 2 ΩR3 = 25 ΩR4 = 10 Ω
VR3 = V

Answer key

  1. 1. IR3 = 6.667 A
  2. 2. I = 30 mA
  3. 3. I = 8.1 mA
  4. 4. IR1 = 1.395 A
  5. 5. V2 = 32.5 V
  6. 6. VR3 = 17.74 V

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