Superposition worksheet with answers

Free printable Superposition worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy

Use superposition to find the voltage V_R3 across R₃ with the polarity shown.

V₁ = 20 VV₂ = 15 VR₁ = 6 ΩR₂ = 3 ΩR₃ = 10 Ω

V_R3 = V

2.Easy

A linear resistive circuit contains two independent voltage sources, V₁ = 24 V and V₂ = 15 V. With both sources on, the current through the load resistor is I = 15.5 mA. With V₂ switched off (replaced by a short circuit) and V₁ unchanged, the load current is 14 mA. Find the load current I when V₁ is switched off and only V₂ = 15 V is active.

I = 15.5 mA (both sources)I = 14 mA (only V₁)

I = mA

3.Medium

Use superposition to find the current I_R3 through R₃ in the direction of the arrow.

V₁ = 30 VI_s = 2.5 AR₁ = 12 ΩR₂ = 10 ΩR₃ = 4 ΩR₄ = 3 Ω

I_R3 = A

4.Medium

Use superposition to find the voltage V_R4 across R₄ with the polarity shown.

V₁ = 10 VI_s = 5 AR₁ = 6 ΩR₂ = 6 ΩR₃ = 3 ΩR₄ = 15 Ω

V_R4 = V

5.Hard

Use superposition to find the voltage V_R2 across R₂ with the polarity shown.

V₁ = 10 VI_s = 4 AV₂ = 12 VR₁ = 12 ΩR₂ = 3 ΩR₃ = 25 ΩR₄ = 15 Ω

V_R2 = V

6.Hard

Find the value of the voltage source V₂ (polarity as shown) that makes the current I_R3 through R₃ equal to zero.

V₁ = 18 VI_s = 4 AR₁ = 15 ΩR₂ = 3 ΩR₃ = 6 ΩR₄ = 12 Ω

V₂ = V

Answer key

1. V_R3 = 13.89 V
2. I = 1.5 mA
3. I_R3 = 1.697 A
4. V_R4 = −17.86 V
5. V_R2 = −7.497 V
6. V₂ = 30 V

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