Use superposition to find the current IR3 through R3 in the direction of the arrow.
Superposition worksheet with answers
1.Easy
V1 = 15 VV2 = 10 VR1 = 5 ΩR2 = 3 ΩR3 = 8 Ω
IR3 = A
2.Easy
Use superposition to find the current IR1 through R1 in the direction of the arrow.
V1 = 8 VIs = 1 AR1 = 8 ΩR2 = 5 Ω
IR1 = A
3.Medium
A linear resistive circuit contains one voltage source Vs and one current source Is. The current I through a load resistor is measured twice: with Vs = 5 V and Is = 3 mA, I = 5.25 mA; with Vs = 8 V and Is = 10 mA, I = 4.5 mA. Find the load current I when Vs = 4 V and Is = 5 mA.
5 V, 3 mA → 5.25 mA8 V, 10 mA → 4.5 mAVs = 4 V, Is = 5 mA
I = mA
4.Medium
Find the value of the current source Is (direction as shown) that makes the current IR3 through R3 equal to zero.
V1 = 18 VR1 = 4 ΩR2 = 12 ΩR3 = 12 ΩR4 = 3 Ω
Is = A
5.Hard
Find the value of the voltage source V2 (polarity as shown) that makes the current IR3 through R3 equal to zero.
V1 = 5 VIs = 2 AR1 = 25 ΩR2 = 20 ΩR3 = 30 ΩR4 = 6 Ω
V2 = V
6.Hard
Use superposition to find the voltage VR2 across R2 with the polarity shown.
V1 = 36 VIs = 3 AV2 = 6 VR1 = 15 ΩR2 = 10 ΩR3 = 8 ΩR4 = 2 Ω
VR2 = V
Answer key
- 1. IR3 = 1.203 A
- 2. IR1 = 1 A
- 3. I = 2.25 mA
- 4. Is = 4.5 A
- 5. V2 = 6.8 V
- 6. VR2 = −7.273 V
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