Superposition worksheet with answers

Free printable Superposition worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

For teachers: free to print, copy and use in class. Every new worksheet has new values and its own answer key. A link to ExamProblems on your course page is appreciated.

Name: ____________________   Date: ____________

1.Easy
R1​ = 4 ΩIR1​+−V1​10 VR2​3 ΩAIs​3 A

Use superposition to find the current IR1 through R1 in the direction of the arrow.

V1 = 10 VIs = 3 AR1 = 4 ΩR2 = 3 Ω
IR1 = A
2.Easy
R1​ = 8 ΩR2​ = 4 ΩIR2​+−V1​10 VR3​3 ΩA+−V2​20 V

Use superposition to find the contribution IR2″ of V2 alone to the current IR2 through R2 in the direction of the arrow.

V1 = 10 VV2 = 20 VR1 = 8 ΩR2 = 4 ΩR3 = 3 Ω
IR2″ = A
3.Medium
linear circuitVs​Is​IRL​

A linear resistive circuit contains one voltage source Vs and one current source Is. The current I through a load resistor is measured twice: with Vs = 20 V and Is = 2 mA, I = 24.5 mA; with Vs = 5 V and Is = 4 mA, I = 7 mA. Find the load current I when Vs = 2 V and Is = 1 mA.

20 V, 2 mA → 24.5 mA5 V, 4 mA → 7 mAVs = 2 V, Is = 1 mA
I = mA
4.Medium
linear circuitVs​Is​IRL​

A linear resistive circuit contains one voltage source Vs and one current source Is. The current I through a load resistor is measured twice: with Vs = 10 V and Is = 10 mA, I = 10 mA; with Vs = 8 V and Is = 2 mA, I = 5 mA. Find the load current I when Vs = 10 V and Is = 8 mA.

10 V, 10 mA → 10 mA8 V, 2 mA → 5 mAVs = 10 V, Is = 8 mA
I = mA
5.Hard
R1​ = 30 ΩR2​ = 15 ΩR4​ = 30 Ω+−V1​15 VR3​2 ΩIR3​AIs​1.5 AB+−V2​?

Find the value of the voltage source V2 (polarity as shown) that makes the current IR3 through R3 equal to zero.

V1 = 15 VIs = 1.5 AR1 = 30 ΩR2 = 15 ΩR3 = 2 ΩR4 = 30 Ω
V2 = V
6.Hard
R1​ = 10 ΩR2​ = 12 Ω−+VR2​R4​ = 15 Ω+−V1​10 VR3​8 ΩAIs​1.5 AB−+V2​5 V

Use superposition to find the voltage VR2 across R2 with the polarity shown.

V1 = 10 VIs = 1.5 AV2 = 5 VR1 = 10 ΩR2 = 12 ΩR3 = 8 ΩR4 = 15 Ω
VR2 = V

Answer key

  1. 1. IR1 = 0.1429 A
  2. 2. IR2″ = −3.235 A
  3. 3. I = 2.65 mA
  4. 4. I = 9 mA
  5. 5. V2 = 22.5 V
  6. 6. VR2 = 4.982 V

Full step-by-step solutions: practise this topic on examproblems.com.