Superposition worksheet with answers

Free printable Superposition worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy

Use superposition to find the voltage V_R3 across R₃ with the polarity shown.

V₁ = 24 VV₂ = 24 VR₁ = 2 ΩR₂ = 2 ΩR₃ = 8 Ω

V_R3 = V

2.Easy

Use superposition to find the current I_R2 through R₂ in the direction of the arrow.

V₁ = 12 VV₂ = 12 VR₁ = 12 ΩR₂ = 5 ΩR₃ = 3 Ω

I_R2 = A

3.Medium

Find the value of the current source I_s (direction as shown) that makes the current I_R3 through R₃ equal to zero.

V₁ = 10 VR₁ = 6 ΩR₂ = 12 ΩR₃ = 10 ΩR₄ = 5 Ω

I_s = A

4.Medium

A linear resistive circuit contains one voltage source V_s and one current source I_s. The current I through a load resistor is measured twice: with V_s = 8 V and I_s = 6 mA, I = 7.9 mA; with V_s = 8 V and I_s = 3 mA, I = 7.15 mA. Find the load current I when V_s = 12 V and I_s = 10 mA.

8 V, 6 mA → 7.9 mA8 V, 3 mA → 7.15 mAV_s = 12 V, I_s = 10 mA

I = mA

5.Hard

Find the value of the voltage source V₂ (polarity as shown) that makes the current I_R3 through R₃ equal to zero.

V₁ = 15 VI_s = 1 AR₁ = 20 ΩR₂ = 2 ΩR₃ = 25 ΩR₄ = 10 Ω

V₂ = V

6.Hard

Use superposition to find the power P_R2 absorbed by R₂.

V₁ = 5 VI_s = 3 AV₂ = 15 VR₁ = 20 ΩR₂ = 15 ΩR₃ = 5 ΩR₄ = 8 Ω

P_R2 = W

Answer key

1. V_R3 = 21.33 V
2. I_R2 = −1.297 A
3. I_s = 1.333 A
4. I = 12.1 mA
5. V₂ = 1 V
6. P_R2 = 29.71 W

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