A linear resistive circuit contains two independent voltage sources, V1 = 5 V and V2 = 24 V. With both sources on, the current through the load resistor is I = 11.5 mA. With V2 switched off (replaced by a short circuit) and V1 unchanged, the load current is 4 mA. Find the load current I when V1 is switched off and only V2 = 24 V is active.
Superposition worksheet with answers
1.Easy
I = 11.5 mA (both sources)I = 4 mA (only V1)
I = mA
2.Easy
Use superposition to find the current IR1 through R1 in the direction of the arrow.
V1 = 24 VIs = 2 AR1 = 3 ΩR2 = 8 Ω
IR1 = A
3.Medium
Use superposition to find the voltage VR4 across R4 with the polarity shown.
V1 = 30 VIs = 2 AR1 = 8 ΩR2 = 20 ΩR3 = 10 ΩR4 = 3 Ω
VR4 = V
4.Medium
Use superposition to find the current IR2 through R2 in the direction of the arrow.
V1 = 6 VIs = 2 AR1 = 15 ΩR2 = 12 ΩR3 = 4 ΩR4 = 15 Ω
IR2 = A
5.Hard
Use superposition to find the power PR2 absorbed by R2.
V1 = 30 VIs = 4 AV2 = 30 VR1 = 2 ΩR2 = 25 ΩR3 = 5 ΩR4 = 3 Ω
PR2 = W
6.Hard
Use superposition to find the current IR3 through R3 in the direction of the arrow.
V1 = 24 VIs = 4 AV2 = 6 VR1 = 10 ΩR2 = 8 ΩR3 = 15 ΩR4 = 25 Ω
IR3 = A
Answer key
- 1. I = 7.5 mA
- 2. IR1 = 0.7273 A
- 3. VR4 = −8.473 V
- 4. IR2 = −0.8139 A
- 5. PR2 = 0.3393 W
- 6. IR3 = 1.899 A
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