Superposition worksheet with answers

Free printable Superposition worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
linear circuitV1​ = 5 VV2​ = 24 VIRL​

A linear resistive circuit contains two independent voltage sources, V1 = 5 V and V2 = 24 V. With both sources on, the current through the load resistor is I = 11.5 mA. With V2 switched off (replaced by a short circuit) and V1 unchanged, the load current is 4 mA. Find the load current I when V1 is switched off and only V2 = 24 V is active.

I = 11.5 mA (both sources)I = 4 mA (only V1)
I = mA
2.Easy
R1​ = 3 ΩIR1​+−V1​24 VR2​8 ΩAIs​2 A

Use superposition to find the current IR1 through R1 in the direction of the arrow.

V1 = 24 VIs = 2 AR1 = 3 ΩR2 = 8 Ω
IR1 = A
3.Medium
R1​ = 8 ΩR3​ = 10 Ω+−V1​30 VR2​20 ΩAR4​3 Ω−+VR4​BIs​2 A

Use superposition to find the voltage VR4 across R4 with the polarity shown.

V1 = 30 VIs = 2 AR1 = 8 ΩR2 = 20 ΩR3 = 10 ΩR4 = 3 Ω
VR4 = V
4.Medium
R1​ = 15 ΩR3​ = 4 Ω+−V1​6 VR2​12 ΩIR2​AR4​15 ΩBIs​2 A

Use superposition to find the current IR2 through R2 in the direction of the arrow.

V1 = 6 VIs = 2 AR1 = 15 ΩR2 = 12 ΩR3 = 4 ΩR4 = 15 Ω
IR2 = A
5.Hard
R1​ = 2 ΩR2​ = 25 ΩIR2​R4​ = 3 Ω+−V1​30 VR3​5 ΩAIs​4 AB+−V2​30 V

Use superposition to find the power PR2 absorbed by R2.

V1 = 30 VIs = 4 AV2 = 30 VR1 = 2 ΩR2 = 25 ΩR3 = 5 ΩR4 = 3 Ω
PR2 = W
6.Hard
R1​ = 10 ΩR2​ = 8 ΩR4​ = 25 Ω+−V1​24 VR3​15 ΩIR3​AIs​4 AB+−V2​6 V

Use superposition to find the current IR3 through R3 in the direction of the arrow.

V1 = 24 VIs = 4 AV2 = 6 VR1 = 10 ΩR2 = 8 ΩR3 = 15 ΩR4 = 25 Ω
IR3 = A

Answer key

  1. 1. I = 7.5 mA
  2. 2. IR1 = 0.7273 A
  3. 3. VR4 = −8.473 V
  4. 4. IR2 = −0.8139 A
  5. 5. PR2 = 0.3393 W
  6. 6. IR3 = 1.899 A

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