Superposition worksheet with answers

Free printable Superposition worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy

Use superposition to find the current I_R3 through R₃ in the direction of the arrow.

V₁ = 24 VV₂ = 10 VR₁ = 3 ΩR₂ = 2 ΩR₃ = 6 Ω

I_R3 = A

2.Easy

Use superposition to find the voltage V_R3 across R₃ with the polarity shown.

V₁ = 18 VV₂ = 10 VR₁ = 5 ΩR₂ = 3 ΩR₃ = 3 Ω

V_R3 = V

3.Medium

A linear resistive circuit contains one voltage source V_s and one current source I_s. The current I through a load resistor is measured twice: with V_s = 2 V and I_s = 3 mA, I = 2.7 mA; with V_s = 2 V and I_s = 8 mA, I = 5.2 mA. Find the load current I when V_s = 4 V and I_s = 2 mA.

2 V, 3 mA → 2.7 mA2 V, 8 mA → 5.2 mAV_s = 4 V, I_s = 2 mA

I = mA

4.Medium

Use superposition to find the current I_R2 through R₂ in the direction of the arrow.

V₁ = 10 VI_s = 1 AR₁ = 4 ΩR₂ = 4 ΩR₃ = 4 ΩR₄ = 12 Ω

I_R2 = A

5.Hard

Use superposition to find the power P_R3 absorbed by R₃.

V₁ = 5 VI_s = 3 AV₂ = 36 VR₁ = 25 ΩR₂ = 20 ΩR₃ = 5 ΩR₄ = 4 Ω

P_R3 = W

6.Hard

A linear resistive circuit contains three independent sources: V₁, V₂ and I_s. The current I through a load is measured three times. With all sources at their normal values, I = 6.5 mA. With V₁ doubled and the other two unchanged, I = 7 mA. With the direction of I_s reversed and the other two unchanged, I = 18.5 mA. Find the load current I when V₂ is switched off and V₁ and I_s have their normal values.

normal: I = 6.5 mA2·V₁: I = 7 mA−I_s: I = 18.5 mA

I = mA

Answer key

1. I_R3 = 2.167 A
2. V_R3 = 8 V
3. I = 3.4 mA
4. I_R2 = 1.444 A
5. P_R3 = 8.168 W
6. I = −5.5 mA

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