Superposition worksheet with answers

Free printable Superposition worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy

Use superposition to find the current I_R1 through R₁ in the direction of the arrow.

V₁ = 12 VI_s = 2 AR₁ = 12 ΩR₂ = 3 Ω

I_R1 = A

2.Easy

Use superposition to find the node voltage V_A (measured from ground).

V₁ = 15 VI_s = 3 AR₁ = 3 ΩR₂ = 10 Ω

V_A = V

3.Medium

Find the value of the current source I_s (direction as shown) that makes the current I_R3 through R₃ equal to zero.

V₁ = 12 VR₁ = 12 ΩR₂ = 2 ΩR₃ = 15 ΩR₄ = 3 Ω

I_s = A

4.Medium

Use superposition to find the current I_R2 through R₂ in the direction of the arrow.

V₁ = 15 VI_s = 1.5 AR₁ = 15 ΩR₂ = 12 ΩR₃ = 12 ΩR₄ = 5 Ω

I_R2 = A

5.Hard

Use superposition to find the voltage V_R2 across R₂ with the polarity shown.

V₁ = 30 VI_s = 1.5 AV₂ = 6 VR₁ = 2 ΩR₂ = 2 ΩR₃ = 20 ΩR₄ = 15 Ω

V_R2 = V

6.Hard

A linear resistive circuit contains three independent sources: V₁, V₂ and I_s. The current I through a load is measured three times. With all sources at their normal values, I = 15.5 mA. With V₁ doubled and the other two unchanged, I = 19.5 mA. With the direction of I_s reversed and the other two unchanged, I = 0.5 mA. Find the load current I when V₂ is switched off and V₁ and I_s have their normal values.

normal: I = 15.5 mA2·V₁: I = 19.5 mA−I_s: I = 0.5 mA

I = mA

Answer key

1. I_R1 = 0.4 A
2. V_A = 4.615 V
3. I_s = 0.5714 A
4. I_R2 = 0.5751 A
5. V_R2 = 0.1304 V
6. I = 11.5 mA

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