Use superposition to find the current IR3 through R3 in the direction of the arrow.
Superposition worksheet with answers
1.Easy
V1 = 12 VV2 = 6 VR1 = 6 ΩR2 = 12 ΩR3 = 12 Ω
IR3 = A
2.Easy
Use superposition to find the contribution IR2″ of V2 alone to the current IR2 through R2 in the direction of the arrow.
V1 = 10 VV2 = 6 VR1 = 8 ΩR2 = 10 ΩR3 = 8 Ω
IR2″ = A
3.Medium
Use superposition to find the current IR1 through R1 in the direction of the arrow.
V1 = 12 VIs = 2.5 AR1 = 4 ΩR2 = 5 ΩR3 = 12 ΩR4 = 5 Ω
IR1 = A
4.Medium
Use superposition to find the voltage VR4 across R4 with the polarity shown.
V1 = 10 VIs = 4 AR1 = 2 ΩR2 = 5 ΩR3 = 20 ΩR4 = 15 Ω
VR4 = V
5.Hard
Use superposition to find the power PR2 absorbed by R2.
V1 = 12 VIs = 4 AV2 = 10 VR1 = 8 ΩR2 = 6 ΩR3 = 20 ΩR4 = 5 Ω
PR2 = W
6.Hard
Use superposition to find the power PR1 absorbed by R1.
V1 = 24 VIs = 6 AV2 = 5 VR1 = 4 ΩR2 = 15 ΩR3 = 12 ΩR4 = 8 Ω
PR1 = W
Answer key
- 1. IR3 = 0.625 A
- 2. IR2″ = −0.4286 A
- 3. IR1 = 1.165 A
- 4. VR4 = 38.24 V
- 5. PR2 = 9.862 W
- 6. PR1 = 2.426 W
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