Superposition worksheet with answers

Free printable Superposition worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy

Use superposition to find the current I_R2 through R₂ in the direction of the arrow.

V₁ = 6 VV₂ = 12 VR₁ = 2 ΩR₂ = 3 ΩR₃ = 8 Ω

I_R2 = A

2.Easy

A linear resistive circuit contains two independent voltage sources, V₁ = 9 V and V₂ = 12 V. With both sources on, the current through the load resistor is I = 7 mA. With V₂ switched off (replaced by a short circuit) and V₁ unchanged, the load current is 5 mA. Find the load current I when V₁ is switched off and only V₂ = 12 V is active.

I = 7 mA (both sources)I = 5 mA (only V₁)

I = mA

3.Medium

A linear resistive circuit contains one voltage source V_s and one current source I_s. The current I through a load resistor is measured twice: with V_s = 15 V and I_s = 8 mA, I = −2.25 mA; with V_s = 15 V and I_s = 10 mA, I = −3.75 mA. Find the load current I when V_s = 20 V and I_s = 10 mA.

15 V, 8 mA → −2.25 mA15 V, 10 mA → −3.75 mAV_s = 20 V, I_s = 10 mA

I = mA

4.Medium

Use superposition to find the current I_R3 through R₃ in the direction of the arrow.

V₁ = 9 VI_s = 2.5 AR₁ = 20 ΩR₂ = 8 ΩR₃ = 4 ΩR₄ = 3 Ω

I_R3 = A

5.Hard

Use superposition to find the power P_R3 absorbed by R₃.

V₁ = 30 VI_s = 2.5 AV₂ = 18 VR₁ = 8 ΩR₂ = 6 ΩR₃ = 3 ΩR₄ = 3 Ω

P_R3 = W

6.Hard

Use superposition to find the voltage V_R2 across R₂ with the polarity shown.

V₁ = 9 VI_s = 2.5 AV₂ = 15 VR₁ = 4 ΩR₂ = 30 ΩR₃ = 3 ΩR₄ = 3 Ω

V_R2 = V

Answer key

1. I_R2 = −1.565 A
2. I = 2 mA
3. I = −2.5 mA
4. I_R3 = −0.3876 A
5. P_R3 = 6.86 W
6. V_R2 = 16.11 V

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