An ideal transformer must step 3840 V down to 240 V. Its primary winding has 1920 turns. How many turns N2 does the secondary winding need?
Transformers worksheet with answers
An ideal transformer has 250 turns on its primary winding and 5000 turns on its secondary winding. The primary is connected to a 110 V AC supply. Find the secondary voltage V2.
A single-phase 50 kVA, 2400/240 V transformer operates at its rated load. Treat it as ideal. Find the current ILV in the low-voltage winding.
An ideal transformer with a turns ratio N₁:N₂ = 2:1 has 460 V applied to its primary winding. A 48 Ω resistor is connected across the secondary winding. Find the primary current I1.
A single-phase 50 kVA transformer has a core loss of 150 W. At rated load and a power factor of 0.85 lagging its efficiency is 97.5%. Find the full-load copper loss Pcu,fl in watts.
A single-phase 250 kVA transformer has a core loss of 1000 W and a copper loss of 3000 W at rated load. At what load Sη,max, in kVA, is its efficiency highest?
Answer key
- 1. N2 = 120
- 2. V2 = 2200 V
- 3. ILV = 208.3 A
- 4. I1 = 2.396 A
- 5. Pcu,fl = 939.7 W
- 6. Sη,max = 144.3 kVA
Full step-by-step solutions: practise this topic on examproblems.com.