ECG interpretation practice: rhythm strips and practice test

Reading lead II rhythm strips: heart rate by the 300, 1500 and 6-second methods, the PR, QRS and QT intervals and the QTc, and recognising sinus rhythms, atrial fibrillation and flutter, junctional rhythm, PVCs, the AV blocks and the ventricular rhythms. The hardest level adds the rhythms of ACLS-style rhythm-strip practice: SVT, torsades de pointes, idioventricular rhythm, sinus arrest, paced rhythms with failure to capture, 2:1 block and PEA. Every strip is drawn on standard ECG paper, so you measure it as in the exam.

Cram pack (PDF)Formula sheets, method steps and practice problems with full solutions, ready to print.

Topics in this course

  1. ECG rhythm strip interpretationrate and intervals · QT and rhythm recognition · heart blocks and ventricular rhythmscalculations
  2. Human physiologykey terms and facts · applying the concepts · cases and analysismultiple choice

Exam tips for ECG Interpretation

  • Use the same five steps for every strip: rate, rhythm, P waves, PR interval, QRS duration. Name the rhythm only at the end.
  • Convert boxes to seconds before you use a formula: one small box is 0.04 s, one large box 0.20 s.
  • In any slow or irregular rhythm, march out the P waves; a P wave hidden in a T wave changes the answer.

Worked examples

ECG rhythm strip interpretationEasy
II25 mm/s · 10 mm/mV

Measure the QRS duration on this lead II strip, in seconds.

lead II, 25 mm/s, 10 mm/mV1 small box = 0.04 s, 1 large box = 0.20 sstrip length 6 s

Find QRS (s)

Show hints
  1. The QRS starts where the trace leaves the baseline after the PR segment (the first deflection, Q or R).
  2. It ends at the J point, where the S wave returns to the baseline.
  3. The QRS is 2 small boxes wide.
Show the answer and the step-by-step solution

Reading the paper: ECG paper runs at 25 mm/s, so one small box (1 mm) is 0.04 s and one large box (5 mm) is 0.20 s; vertically 10 mm is 1 mV. For a regular rhythm the heart rate is 300 ÷ the number of large boxes between two R waves, or 1500 ÷ the number of small boxes (more exact). For an irregular rhythm count the QRS complexes in a 6-second strip and multiply by 10. Textbook normal values: PR interval 0.12–0.20 s (3–5 small boxes) from the start of the P wave to the start of the QRS; QRS duration below 0.12 s (under 3 small boxes); a rhythm is regular when the R–R intervals are the same.

Measure

2 small boxes from the start of the QRS to the J point

Convert

QRS = 2 × 0.04 s = 0.08 s

Answer

QRS = 0.08 s

Below 0.12 s: a narrow QRS, normal conduction through the ventricles.

Human physiologyMedium

Which protein forms the mesh that stabilises a blood clot?

  1. ACollagen
  2. BAlbumin
  3. CFibrin
  4. DThrombin
Show hints
  1. Thrombin makes it from a soluble plasma precursor.
  2. Two wrong answers are now crossed out. One of the remaining two is right.
Show the answer and explanation

Why this is the answer

Thrombin converts soluble fibrinogen into insoluble fibrin strands, which bind the platelet plug and trap red cells to form a stable clot.

Answer

C · Fibrin

How practising works

  • “Practise this course” mixes problems from all its topics, like a real exam.
  • Every problem has new values, so you learn the method instead of an answer.
  • Stuck? Open a small hint first, and the full explanation only when you need it.
  • Mock exams are timed and have no hints, and you get your score and a full review at the end.

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