Cari had L = limx→1 (x2 + 4x − 5)/(x − 1).
Lembaran kerja Had dengan jawapan
1.Mudah
f(x) = (x2 + 4x − 5)/(x − 1)x → 1
L =
2.Mudah
Cari had L = limx→16 (√x − 4)/(x − 16).
f(x) = (√x − 4)/(x − 16)x → 16
L =
3.Sederhana
Cari had L = limx→∞ (√(9x2 − 10x) − 3x).
f(x) = √(9x2 − 10x) − 3xx → ∞
L =
4.Sederhana
Cari had L = limx→∞ (6x2 − 2x − 6)/(3x2 + 4x + 1).
f(x) = (6x2 − 2x − 6)/(3x2 + 4x + 1)x → ∞
L =
5.Sukar
Cari had L = limx→0 ln(1 + 4x)/sin(x), dengan x dalam radian.
f(x) = ln(1 + 4x)/sin(x)x → 0
L =
6.Sukar
Cari had L = limx→0 (e−2x − 1 + 2x)/x².
f(x) = (e−2x − 1 + 2x)/x²x → 0
L =
Kunci jawapan
- 1. L = 6
- 2. L = 0.125
- 3. L = −1.667
- 4. L = 2
- 5. L = 4
- 6. L = 2
Penyelesaian langkah demi langkah yang lengkap: berlatih topik ini di examproblems.com.