1.Mudah
Cari had L = limx→1 (√x − 1)/(x − 1).
f(x) = (√x − 1)/(x − 1)x → 1
L =
Cari had L = limx→1 (√x − 1)/(x − 1).
Cari had L = limx→2 (x4 − 16)/(x − 2).
Cari had L = limx→∞ (√(x2 + 7x) − x).
Cari had L = limx→∞ (√(x2 − 4x) − x).
Cari had L = limx→0 (e−0.5x − 1 + 0.5x)/x².
Cari had L = limx→0 (e−2x − 1 + 2x)/x².
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